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Linux/arch/alpha/lib/memchr.S

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Diff markup

Differences between /arch/alpha/lib/memchr.S (Architecture i386) and /arch/mips/lib/memchr.S (Architecture mips)


  1 /* Copyright (C) 1996 Free Software Foundation    
  2    This file is part of the GNU C Library.        
  3    Contributed by David Mosberger (davidm@cs.a    
  4                                                   
  5    The GNU C Library is free software; you can    
  6    modify it under the terms of the GNU Librar    
  7    published by the Free Software Foundation;     
  8    License, or (at your option) any later vers    
  9                                                   
 10    The GNU C Library is distributed in the hop    
 11    but WITHOUT ANY WARRANTY; without even the     
 12    MERCHANTABILITY or FITNESS FOR A PARTICULAR    
 13    Library General Public License for more det    
 14                                                   
 15    You should have received a copy of the GNU     
 16    License along with the GNU C Library; see t    
 17    write to the Free Software Foundation, Inc.    
 18    Boston, MA 02111-1307, USA.  */                
 19                                                   
 20 /* Finds characters in a memory area.  Optimiz    
 21                                                   
 22       - memory accessed as aligned quadwords o    
 23       - uses cmpbge to compare 8 bytes in para    
 24       - does binary search to find 0 byte in l    
 25         quadword (HAKMEM needed 12 instruction    
 26         do this instead of the 9 instructions     
 27         binary search needs).                     
 28                                                   
 29 For correctness consider that:                    
 30                                                   
 31       - only minimum number of quadwords may b    
 32       - the third argument is an unsigned long    
 33 */                                                
 34 #include <linux/export.h>                         
 35         .set noreorder                            
 36         .set noat                                 
 37                                                   
 38         .globl memchr                             
 39         .ent memchr                               
 40 memchr:                                           
 41         .frame $30,0,$26,0                        
 42         .prologue 0                               
 43                                                   
 44         # Hack -- if someone passes in (size_t    
 45         # search til the end of the address sp    
 46         # below when we find the address of th    
 47         # that we will never have a 56-bit add    
 48         # the length is the easiest way to avo    
 49         zap     $18, 0x80, $5   #-e0    :         
 50                                                   
 51         beq     $18, $not_found # .. e1 :         
 52         ldq_u   $1, 0($16)      # e1    : load    
 53         insbl   $17, 1, $2      # .. e0 : $2 =    
 54         and     $17, 0xff, $17  #-e0    : $17     
 55         cmpult  $18, 9, $4      # .. e1 :         
 56         or      $2, $17, $17    # e0    : $17     
 57         lda     $3, -1($31)     # .. e1 :         
 58         sll     $17, 16, $2     #-e0    : $2 =    
 59         addq    $16, $5, $5     # .. e1 :         
 60         or      $2, $17, $17    # e1    : $17     
 61         unop                    #       :         
 62         sll     $17, 32, $2     #-e0    : $2 =    
 63         or      $2, $17, $17    # e1    : $17     
 64         extql   $1, $16, $7     # e0    :         
 65         beq     $4, $first_quad # .. e1 :         
 66                                                   
 67         ldq_u   $6, -1($5)      #-e1    : eigh    
 68         extqh   $6, $16, $6     # .. e0 :         
 69         mov     $16, $0         # e0    :         
 70         or      $7, $6, $1      # .. e1 : $1 =    
 71                                                   
 72         # Deal with the case where at most 8 b    
 73         # in $1.  E.g.:                           
 74         #       $18 = 6                           
 75         #       $1 = ????c6c5c4c3c2c1             
 76 $last_quad:                                       
 77         negq    $18, $6         #-e0    :         
 78         xor     $17, $1, $1     # .. e1 :         
 79         srl     $3, $6, $6      # e0    : $6 =    
 80         cmpbge  $31, $1, $2     # .. e1 :         
 81         and     $2, $6, $2      #-e0    :         
 82         beq     $2, $not_found  # .. e1 :         
 83                                                   
 84 $found_it:                                        
 85         # Now, determine which byte matched:      
 86         negq    $2, $3          # e0    :         
 87         and     $2, $3, $2      # e1    :         
 88                                                   
 89         and     $2, 0x0f, $1    #-e0    :         
 90         addq    $0, 4, $3       # .. e1 :         
 91         cmoveq  $1, $3, $0      # e0    :         
 92                                                   
 93         addq    $0, 2, $3       # .. e1 :         
 94         and     $2, 0x33, $1    #-e0    :         
 95         cmoveq  $1, $3, $0      # .. e1 :         
 96                                                   
 97         and     $2, 0x55, $1    # e0    :         
 98         addq    $0, 1, $3       # .. e1 :         
 99         cmoveq  $1, $3, $0      #-e0    :         
100                                                   
101 $done:  ret                     # .. e1 :         
102                                                   
103         # Deal with the case where $18 > 8 byt    
104         # searched.  $16 may not be aligned.      
105         .align 4                                  
106 $first_quad:                                      
107         andnot  $16, 0x7, $0    #-e1    :         
108         insqh   $3, $16, $2     # .. e0 : $2 =    
109         xor     $1, $17, $1     # e0    :         
110         or      $1, $2, $1      # e1    : $1 =    
111         cmpbge  $31, $1, $2     #-e0    :         
112         bne     $2, $found_it   # .. e1 :         
113                                                   
114         # At least one byte left to process.      
115                                                   
116         ldq     $1, 8($0)       # e0    :         
117         subq    $5, 1, $18      # .. e1 :         
118         addq    $0, 8, $0       #-e0    :         
119                                                   
120         # Make $18 point to last quad to be ac    
121         # last quad may or may not be partial)    
122                                                   
123         andnot  $18, 0x7, $18   # .. e1 :         
124         cmpult  $0, $18, $2     # e0    :         
125         beq     $2, $final      # .. e1 :         
126                                                   
127         # At least two quads remain to be acce    
128                                                   
129         subq    $18, $0, $4     #-e0    : $4 <    
130         and     $4, 8, $4       # e1    : odd     
131         bne     $4, $odd_quad_count # e1 :        
132                                                   
133         # At least three quads remain to be ac    
134                                                   
135         mov     $1, $4          # e0    : move    
136                                                   
137         .align  4                                 
138 $unrolled_loop:                                   
139         ldq     $1, 8($0)       #-e0    : pref    
140         xor     $17, $4, $2     # .. e1 :         
141         cmpbge  $31, $2, $2     # e0    :         
142         bne     $2, $found_it   # .. e1 :         
143                                                   
144         addq    $0, 8, $0       #-e0    :         
145 $odd_quad_count:                                  
146         xor     $17, $1, $2     # .. e1 :         
147         ldq     $4, 8($0)       # e0    : pref    
148         cmpbge  $31, $2, $2     # .. e1 :         
149         addq    $0, 8, $6       #-e0    :         
150         bne     $2, $found_it   # .. e1 :         
151                                                   
152         cmpult  $6, $18, $6     # e0    :         
153         addq    $0, 8, $0       # .. e1 :         
154         bne     $6, $unrolled_loop #-e1 :         
155                                                   
156         mov     $4, $1          # e0    : move    
157 $final: subq    $5, $0, $18     # .. e1 : $18     
158         bne     $18, $last_quad # e1    :         
159                                                   
160 $not_found:                                       
161         mov     $31, $0         #-e0    :         
162         ret                     # .. e1 :         
163                                                   
164         .end memchr                               
165         EXPORT_SYMBOL(memchr)                     
                                                      

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