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Linux/arch/microblaze/include/asm/hash.h

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  1 /* SPDX-License-Identifier: GPL-2.0 */
  2 #ifndef _ASM_HASH_H
  3 #define _ASM_HASH_H
  4 
  5 /*
  6  * Fortunately, most people who want to run Linux on Microblaze enable
  7  * both multiplier and barrel shifter, but omitting them is technically
  8  * a supported configuration.
  9  *
 10  * With just a barrel shifter, we can implement an efficient constant
 11  * multiply using shifts and adds.  GCC can find a 9-step solution, but
 12  * this 6-step solution was found by Yevgen Voronenko's implementation
 13  * of the Hcub algorithm at http://spiral.ece.cmu.edu/mcm/gen.html.
 14  *
 15  * That software is really not designed for a single multiplier this large,
 16  * but if you run it enough times with different seeds, it'll find several
 17  * 6-shift, 6-add sequences for computing x * 0x61C88647.  They are all
 18  *      c = (x << 19) + x;
 19  *      a = (x <<  9) + c;
 20  *      b = (x << 23) + a;
 21  *      return (a<<11) + (b<<6) + (c<<3) - b;
 22  * with variations on the order of the final add.
 23  *
 24  * Without even a shifter, it's hopless; any hash function will suck.
 25  */
 26 
 27 #if CONFIG_XILINX_MICROBLAZE0_USE_HW_MUL == 0
 28 
 29 #define HAVE_ARCH__HASH_32 1
 30 
 31 /* Multiply by GOLDEN_RATIO_32 = 0x61C88647 */
 32 static inline u32 __attribute_const__ __hash_32(u32 a)
 33 {
 34 #if CONFIG_XILINX_MICROBLAZE0_USE_BARREL
 35         unsigned int b, c;
 36 
 37         /* Phase 1: Compute three intermediate values */
 38         b =  a << 23;
 39         c = (a << 19) + a;
 40         a = (a <<  9) + c;
 41         b += a;
 42 
 43         /* Phase 2: Compute (a << 11) + (b << 6) + (c << 3) - b */
 44         a <<= 5;
 45         a += b;         /* (a << 5) + b */
 46         a <<= 3;
 47         a += c;         /* (a << 8) + (b << 3) + c */
 48         a <<= 3;
 49         return a - b;   /* (a << 11) + (b << 6) + (c << 3) - b */
 50 #else
 51         /*
 52          * "This is really going to hurt."
 53          *
 54          * Without a barrel shifter, left shifts are implemented as
 55          * repeated additions, and the best we can do is an optimal
 56          * addition-subtraction chain.  This one is not known to be
 57          * optimal, but at 37 steps, it's decent for a 31-bit multiplier.
 58          *
 59          * Question: given its size (37*4 = 148 bytes per instance),
 60          * and slowness, is this worth having inline?
 61          */
 62         unsigned int b, c, d;
 63 
 64         b = a << 4;     /* 4    */
 65         c = b << 1;     /* 1  5 */
 66         b += a;         /* 1  6 */
 67         c += b;         /* 1  7 */
 68         c <<= 3;        /* 3 10 */
 69         c -= a;         /* 1 11 */
 70         d = c << 7;     /* 7 18 */
 71         d += b;         /* 1 19 */
 72         d <<= 8;        /* 8 27 */
 73         d += a;         /* 1 28 */
 74         d <<= 1;        /* 1 29 */
 75         d += b;         /* 1 30 */
 76         d <<= 6;        /* 6 36 */
 77         return d + c;   /* 1 37 total instructions*/
 78 #endif
 79 }
 80 
 81 #endif /* !CONFIG_XILINX_MICROBLAZE0_USE_HW_MUL */
 82 #endif /* _ASM_HASH_H */
 83 

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